Codeforces 600E. Lomsat gelral
学习了一下dsu on tree
所以为啥是dsu而不是dfs on tree???
这道题先把这棵树轻重链剖分了,然后先处理轻儿子,处理完轻儿子后要把轻儿子的贡献都给删了
然后为了计算这个点的贡献,我把所有轻儿子的贡献加回来
如果这个点是个轻儿子,没什么人权,我就再遍历整棵树把它清空
其实我希望的是把整个数组清空,又不能一个一个清,所以把当前子树遍历一遍清空
唔,感觉说的好短,但是确实是这样的……
#include#define fi first#define se second#define pii pair #define mp make_pair#define pb push_back#define space putchar(' ')#define enter putchar('\n')#define eps 1e-10#define MAXN 100005#define ba 47//#define ivorysiusing namespace std;typedef long long int64;typedef unsigned int u32;typedef double db;template void read(T &res) { res = 0;T f = 1;char c = getchar(); while(c < '0' || c > '9') { if(c == '-') f = -1; c = getchar(); } while(c >= '0' && c <= '9') { res = res * 10 +c - '0'; c = getchar(); } res *= f;}template void out(T x) { if(x < 0) {x = -x;putchar('-');} if(x >= 10) { out(x / 10); } putchar('0' + x % 10);}struct node { int to,next;}E[MAXN * 2];int head[MAXN],sumE;int N,c[MAXN],siz[MAXN],son[MAXN];int val[MAXN],mval;int64 sum,ans[MAXN];bool vis[MAXN];void add(int u,int v) { E[++sumE].to = v; E[sumE].next = head[u]; head[u] = sumE;}void dfs(int u,int fa) { siz[u] = 1; for(int i = head[u] ; i ; i = E[i].next) { int v = E[i].to; if(v != fa) { dfs(v,u); siz[u] += siz[v]; if(siz[v] > siz[son[u]]) son[u] = v; } }}void change(int u,int fa,int k) { val[c[u]] += k; if(k == -1) vis[u] = 0; if(val[c[u]] >= mval) { if(val[c[u]] > mval) {mval = val[c[u]];sum = 0;} sum += c[u]; } for(int i = head[u] ; i ; i = E[i].next) { int v = E[i].to; if(v != fa && (!vis[v] || k == -1)) { change(v,u,k); } }}void calc(int u,int fa,bool f) { for(int i = head[u] ; i ; i = E[i].next) { int v = E[i].to; if(v != fa && v != son[u]) { calc(v,u,0); } } if(son[u]) {calc(son[u],u,1);vis[son[u]] = 1;} change(u,fa,1); ans[u] = sum; if(!f) {change(u,fa,-1);sum = 0;mval = 0;}}void Solve() { read(N); for(int i = 1 ; i <= N ; ++i) read(c[i]); int a,b; for(int i = 1 ; i < N ; ++i) { read(a);read(b); add(a,b);add(b,a); } dfs(1,0); calc(1,0,1); for(int i = 1 ; i <= N ; ++i) { out(ans[i]);space; } enter;}int main() {#ifdef ivorysi freopen("f1.in","r",stdin);#endif Solve();}